[c+2(a-b+2c)-a]+2b+3c=

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Solution for [c+2(a-b+2c)-a]+2b+3c= equation:


Simplifying
[c + 2(a + -1b + 2c) + -1a] + 2b + 3c = 0
[c + (a * 2 + -1b * 2 + 2c * 2) + -1a] + 2b + 3c = 0
[c + (2a + -2b + 4c) + -1a] + 2b + 3c = 0

Reorder the terms:
[2a + -1a + -2b + c + 4c] + 2b + 3c = 0

Combine like terms: 2a + -1a = 1a
[1a + -2b + c + 4c] + 2b + 3c = 0

Combine like terms: c + 4c = 5c
[1a + -2b + 5c] + 2b + 3c = 0

Remove brackets around [1a + -2b + 5c]
1a + -2b + 5c + 2b + 3c = 0

Reorder the terms:
1a + -2b + 2b + 5c + 3c = 0

Combine like terms: -2b + 2b = 0
1a + 0 + 5c + 3c = 0
1a + 5c + 3c = 0

Combine like terms: 5c + 3c = 8c
1a + 8c = 0

Solving
1a + 8c = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-8c' to each side of the equation.
1a + 8c + -8c = 0 + -8c

Combine like terms: 8c + -8c = 0
1a + 0 = 0 + -8c
1a = 0 + -8c
Remove the zero:
1a = -8c

Divide each side by '1'.
a = -8c

Simplifying
a = -8c

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